3x^2-18x+24=(x-4)(3x-6)

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Solution for 3x^2-18x+24=(x-4)(3x-6) equation: 



3x^2-18x+24=(x-4)(3x-6)

We move all terms to the left:

3x^2-18x+24-((x-4)(3x-6))=0

We multiply parentheses ..

3x^2-((+3x^2-6x-12x+24))-18x+24=0



We calculate terms in parentheses: -((+3x^2-6x-12x+24)), so:

(+3x^2-6x-12x+24)

We get rid of parentheses

3x^2-6x-12x+24

We add all the numbers together, and all the variables

3x^2-18x+24

Back to the equation:

-(3x^2-18x+24)



We add all the numbers together, and all the variables

3x^2-18x-(3x^2-18x+24)+24=0

We get rid of parentheses

3x^2-3x^2-18x+18x-24+24=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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